Question

How do you differentiate `y = e^(-2x + x^2)`?

Answer 1

`dy/dx = e^(-2x+x^2)(-2+2x)`

Explanation:

Using the chain rule, along with the derivatives `d/dxe^x=e^x` and `d/dxx^n=nx^(n-1)`, we have

`dy/dx = d/dxe^(-2x+x^2)`

`=e^(-2x+x^2)(d/dx(-2x+x^2))`

`=e^(-2x+x^2)(-2+2x)`