# How do you differentiate y = e^9 ln x?

$= {e}^{9} \frac{1}{x}$
${e}^{9}$ is juat a constant and
$\frac{d}{\mathrm{dx}} \alpha \ln x = \alpha \frac{d}{\mathrm{dx}} \ln x = \alpha \frac{1}{x}$