How do you differentiate $y=lnx$ ?

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Answer 1 · 2017-01-20T11:17:21

$1/x$

change to exponent form then differentiate as follows:

$y=lnx=>x=e^y$

differentiated wrt $y$

$(dx)/(dy)=e^y$

$:.(dy)/(dx)=1/e^y=1/x$

How do you differentiate y=lnxy=lnx?