Question

How do you differentiate `y = log (x^2 + 1)`?

Answer 1

`(2x)/(x^2+1)`

Explanation:

Using the `color(blue)" chain rule "`

`d/dx[f(g(x))] = f'(g(x)) . g'(x)`

and the standard derivative `d/dx(logx) = 1/x`

`dy/dx = 1/(x^2+1) .d/dx(x^2+1) = (2x)/(x^2+1)`