Question

How do you differentiate `y = (x) / (x+1)`?

Answer 1

We can use the quotient rule, which states that for `y=f(x)/g(x)`, `(dy)/(dx)=(f'(x)g(x)-f(x)g'(x))/g(x)^2`

Explanation:

Following the formula:

`(dy)/(dx)=((1)(x+1)-(x)(1))/(x+1)^2=(x+1-x)/(x+1)^2=1/(x+1)^2=(x+1)^(-2)`