How do you differentiate #y=xe^x#?

1 Answer
Jan 23, 2017

#frac{"d"}{"d"x}(xe^x) = (1 + x) e^x#

Use the product rule.

Explanation:

The product rule:

If #u# and #v# are differentiable functions of #x#,

and #f = u * v#,

then #f' = u' * v + u * v'#,

where the apostrophe denotes the derivative with respect to #x#.

In the above question, we can see that #x e^x# is a product of #x# and #e^x#, both which are elementary functions.

Thus

#frac{"d"}{"d"x}(xe^x) = frac{"d"}{"d"x}(x) e^x + x frac{"d"}{"d"x}(e^x)#

#= (1) e^x + x (e^x)#

#= (1 + x) e^x#