How do you differentiate ysinx=y?

1 Answer
May 23, 2015

You can use the product rule, like the usual. Just remember that the derivative of y with respect to x in (df)/(dx) is (dy)/(dx).

With f(x): ysinx = y,

(df)/(dx)[ysinx = y] = ycosx + sinx((dy)/(dx)) = (dy)/(dx)

(dy)/(dx)[1-sinx] = ycosx

(dy)/(dx) = (ycosx)/(1-sinx)

If you check Wolfram Alpha, you'll see this, just multiplied by -1.