How do you differentiate $ysinx=y$ ?

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Answer 1 · 2015-05-23T16:33:04

You can use the product rule, like the usual. Just remember that the derivative of y with respect to x in $(df)/(dx)$ is $(dy)/(dx)$ .

With $f(x): ysinx = y$ ,

$(df)/(dx)[ysinx = y] = ycosx + sinx((dy)/(dx)) = (dy)/(dx)$

$(dy)/(dx)[1-sinx] = ycosx$

$(dy)/(dx) = (ycosx)/(1-sinx)$

If you check Wolfram Alpha, you'll see this, just multiplied by $-1$ .

How do you differentiate ysinx=yysinx=y?