How do you divide #2/(m(m+3)) *( 3m + 9)/6#? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer Don't Memorise Jun 19, 2015 #color(red)( =1/m# Explanation: #2/(m(m+3))⋅(3m+9)/6# Here the sign #color(red)(. # between the two expressions denotes multiplication. Taking out #3# from the numerator of the second term #=2/(mcancel((m+3)))⋅((3)cancel((m+3)))/6# #=cancel6/(cancel6m)# #color(red)( =1/m# Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 1434 views around the world You can reuse this answer Creative Commons License