How do you divide #2a^4b^3diva^2b#?

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Answer 1 · 2015-04-11T11:45:24

#2a^4b^3diva^2b#

# = (2a^4b^3)/(a^2*b)#

To make the calculations easier, we group the same coefficients together.

# = 2(a^4/a^2)*((b^3)/b)#

In general, #color(blue)(a^m/a^n = a^(m-n)#

# = 2*a^(4-2)*b^(3-1)#

#color(green)( = 2*a^2*b^2#

Answer 2 · 2015-04-11T11:49:18

#2a^4b^3diva^2b#
or
#(2a^4b^3)/(a^2b)#
can be written as
#2/1 * a^4/a^2 * b^3/b#

using the principle that #x^m/x^n = x^(m-n)#

this can be written as
#2 * a^2 * b^2#
or just

#2a^2b^2#