How do you divide $(2 r^{3} + 5 r^{2} - 2 r - 15) \div (2 r - 3)$ $(2r^3+5r^2-2r-15) div(2r-3)$ ?

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How do you divide $(2 r^{3} + 5 r^{2} - 2 r - 15) \div (2 r - 3)$ $(2r^3+5r^2-2r-15) div(2r-3)$ ?

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Answer 1 · 2017-02-15T12:28:04

The quotient is $= r^{2} + 4 r + 5$ $=r^2+4r+5$

Explanation:

Let's do a long division

$a a a a$ $color(white)(aaaa)$ $2 r^{3} + 5 r^{2} - 2 r - 15$ $2r^3+5r^2-2r-15$ $a a a a$ $color(white)(aaaa)$ $∣$ $|$ $2 r - 3$ $2r-3$

$a a a a$ $color(white)(aaaa)$ $2 r^{3} - 3 r^{2}$ $2r^3-3r^2$ $a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $∣$ $|$ $r^{2} + 4 r + 5$ $r^2+4r+5$

$a a a a a a$ $color(white)(aaaaaa)$ $0 + 8 r^{2} - 2 r$ $0+8r^2-2r$

$a a a a a a a a$ $color(white)(aaaaaaaa)$ $+ 8 r^{2} - 12 r$ $+8r^2-12r$

$a a a a a a a a a a$ $color(white)(aaaaaaaaaa)$ $+ 0 + 10 r - 15$ $+0+10r-15$

$a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaa)$ $+ 10 r - 15$ $+10r-15$

$a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaa)$ $+ 0 - 0$ $+0-0$

The quotient is $= r^{2} + 4 r + 5$ $=r^2+4r+5$

The remainder is $= 0$ $=0$

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How do you divide $(2 r^{3} + 5 r^{2} - 2 r - 15) \div (2 r - 3)$ $(2r^3+5r^2-2r-15) div(2r-3)$ ?

1 Answer

Explanation:

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How do you divide (2r^3+5r^2-2r-15) div(2r-3)(2r3+5r2−2r−15)÷(2r−3)(2r^3+5r^2-2r-15) div(2r-3)?

1 Answer

Explanation:

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How do you divide $(2 r^{3} + 5 r^{2} - 2 r - 15) \div (2 r - 3)$ $(2r^3+5r^2-2r-15) div(2r-3)$ ?