How do you divide $(2r^3+5r^2-2r-15) div(2r-3)$ ?

Question

1921 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-15T12:28:04

The quotient is $=r^2+4r+5$

Let's do a long division

$color(white)(aaaa)$ $2r^3+5r^2-2r-15$ $color(white)(aaaa)$ $|$ $2r-3$

$color(white)(aaaa)$ $2r^3-3r^2$ $color(white)(aaaaaaaaaaaaa)$ $|$ $r^2+4r+5$

$color(white)(aaaaaa)$ $0+8r^2-2r$

$color(white)(aaaaaaaa)$ $+8r^2-12r$

$color(white)(aaaaaaaaaa)$ $+0+10r-15$

$color(white)(aaaaaaaaaaaaaa)$ $+10r-15$

$color(white)(aaaaaaaaaaaaaaaa)$ $+0-0$

The quotient is $=r^2+4r+5$

The remainder is $=0$

How do you divide (2r^3+5r^2-2r-15) div(2r-3)(2r^3+5r^2-2r-15) div(2r-3)?