How do you divide #2y^3+y^2-5y+2# by #y+2#?
1 Answer
Aug 13, 2017
Explanation:
We can split the terms of the dividend into multiples of the divisor as follows:
#2y^3+y^2-5y+2=2y^3+4y^2-3y^2-6y+y+2#
#color(white)(2y^3+y^2-5y+2)=2y^2(y+2)-3y(y+2)+1(y+2)#
#color(white)(2y^3+y^2-5y+2)=(2y^2-3y+1)(y+2)#
So:
#(2y^3+y^2-5y+2)/(y+2) = 2y^2-3y+1#
