How do you divide #(3 + 2i) / (2 - 6i)#?

1 Answer
Mar 28, 2016

You must multiply the whole expression by the conjugate of the denominator, just like you did when you were younger when you were to rationalize the denominator.

Explanation:

The conjugate forms a difference of squares. Therefore, to find it, you must switch the sign in the middle.

Thus, the conjugate is #2 + 6i#

#(3 + 2i)/(2 - 6i) xx (2 + 6i)/(2 + 6i)#

Now multiply. Don't forget that #i^2 = -1#

#(6 + 4i + 12i - 12)/(4 - (36 xx -1)#

Don't forget that you can combine #i#'s with #i#'s but you cannot combine non #i's# with #i's#.

#(6 + 16i - 12)/40#

#(-6 + 16i)/40#

This is as simplified as possible.

Practice exercises:

  1. Evaluate:

a). #(4 + 2i)/(3 - 5i)#

b). #(4x + 3i)/(-x + 2i)#

Good luck!