# How do you divide (49a^3bc^14)/(-7abc^8)?

Jul 9, 2015

For clearness, you may want to split this up, and take the parts piece by piece.

#### Explanation:

$= \frac{49}{-} 7 \cdot {a}^{3} / a \cdot \frac{b}{b} \cdot {c}^{14} / {c}^{8}$

$\frac{49}{-} 7 = - 7$

${a}^{3} / a = {a}^{3 - 1} = {a}^{2}$

$\frac{b}{b} = 1$ (so it disappears later)

${c}^{14} / {c}^{8} = {c}^{14 - 8} = {c}^{6}$

Now put it all together again:

$= - 7 \cdot {a}^{2} \cdot 1 \cdot {c}^{6} = - 7 {a}^{2} {c}^{6}$