How do you divide #(49a^3bc^14)/(-7abc^8)#?

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Answer 1 · 2015-07-09T13:52:18

For clearness, you may want to split this up, and take the parts piece by piece.

#=49/-7*a^3/a*b/b*c^14/c^8#

#49/-7=-7#

#a^3/a=a^(3-1)=a^2#

#b/b=1# (so it disappears later)

#c^14/c^8=c^(14-8)=c^6#

Now put it all together again:

#=-7*a^2*1*c^6=-7a^2c^6#