How do you divide #(4x^3 - 2x^2 + x - 7) ÷ (x - 8) #?

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Answer 1 · 2015-07-01T22:00:42

#(4x^3 -2x^2 +x -7)/(x-8) = 4x^2 +30x +241 + 1921/(x-8)#

You use the process of long division.

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So,

#(4x^3 -2x^2 +x -7)/(x-8) = 4x^2 +30x +241 + 1921/(x-8)#

Check:

#(x-8)(4x^2 +30x +241 + 1921/(x-8))= (x-8)(4x^2+30x+241) +1921#

#= 4x^3 + 30x^2 + 241x -32x^2 – 240x -1928 +1921 = 4x^3 -2x^2 +x -7#