How do you divide #(5x+15)/(12x-6) div(10x^2)/(18)#?

1 Answer
Aug 30, 2015

Answer:

#3/2 * (x+3)/(x-2) * 1/x^2#

Explanation:

Your starting expression looks like this

#(5x + 15)/(12x-6) * 18/(10x^2)#

Factor the numerator and the denominator of the first fraction to get

#(5(x + 3))/(6(x-2))#

The expression will now become

#(color(red)(cancel(color(black)(5)))(x+3))/(color(red)(cancel(color(black)(6)))(x-2)) * (color(red)(cancel(color(black)(18)))3)/(color(red)(cancel(color(black)(10)))2x^2)#

#(x+3)/(x-2) * 3/(2x^2) = color(green)(3/2 * (x+3)/(x-2) * 1/x^2)#