How do you divide #(6-6i)/(-4i)#?

1 Answer
Aug 21, 2016

Answer:

#(6-6i)/-4i=3/2+3/2i#

Explanation:

In any question involving multiplication or division of complex number, one should always remember #i^2=-1#.

In division the way is to rationalize the denominator. As we have only imaginary component in denominator, simply multiplying numerator annd denominator by #i# should rationalize denominator.

Hence, #(6-6i)/(-4i)#

= #((6-6i)×i)/(-4i×i)#

= #(6i-6i^2)/(-4i^2)#

= #(6i+6)/(-4×-1)#

= #(6i+6)/4#

= #6/4+(6i)/4#

= #3/2+3/2i#