How do you divide (8x ^ { 3} + 20x ^ { 2} + 20x + 17) \div ( 4x + 4)?

1 Answer
Jun 7, 2017

8x^3+20x^2+20x+17=(4x+4)color(magenta)((2x^2+3x+2))+color(blue)9

Explanation:

" "8x^3+20x^2+20x+17
color(magenta)(2x^2)(4x+4) ->" "ul(8x^3+8x^2) larr" Subtract"
" "0 +12x^2+20x+17
color(magenta)(+3x)(4x+4)->" "color(white)()ul(12x^2+12x ) larr" Subtract"
" "0+8x+17
color(magenta)(2)(4x+4)->" "color(white)(xxxxxx)ul(8x+8) larr" Subtract"
" "color(blue)(9) larr" Remainder"

Hence, quotient is 2x^2+3x+2 and remainder is 9 and

8x^3+20x^2+20x+17=(4x+4)color(magenta)((2x^2+3x+2))+color(blue)9