# How do you divide (c ^ { 2} + 11c + 18) \div ( c + 9)?

Mar 9, 2017

See the entire solution process below:

#### Explanation:

First, rewrite the expression as:

$\frac{{x}^{2} + 1 x + 18}{c + 9}$

Next, factor the numerator:

$\frac{\left(c + 9\right) \left(c + 2\right)}{c + 9}$

Now, cancel the common terms in the numerator and denominator:

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{\left(c + 9\right)}}} \left(c + 2\right)}{\textcolor{red}{\cancel{\textcolor{b l a c k}{c + 9}}}} \to$

$c + 2$ : where $c + 9 \ne 0$ or $c \ne - 9$