Question

How do you divide `\frac { 2x ^ { 1/ 8} } { x ^ { - 1/ 3} }`?

Answer 1

`2x^(11/24)`

Explanation:

Use exponent rules: `x^m*x^n = x^(m+n)` and `1/x^-2 = x^2`

`(2x^(1/8))/x^(-1/3) = 2x^(1/8)x^(1/3)`

To add the exponents, find a common denominator:

`2x^(1/8)x^(1/3) = 2x^(3/24)x^(8/24) = 2x^(3/24 + 8/24) = 2x^(11/24)`