How do you divide #\frac { 2x ^ { 2} - 2x } { x ^ { 2} - 9} \div \frac { x ^ { 2} + x - 2} { x ^ { 2} + 2x - 3}#?
1 Answer
Nov 25, 2016
We start by switching into a multiplication:
#=> (2x^2 - 2x)/(x^2 - 9) xx (x^2 + 2x - 3)/(x^2 + x - 2)#
We now factor everything to see what we may eliminate.
#=>(2x(x - 1))/((x+ 3)(x - 3)) xx ((x + 3)(x - 1))/((x + 2)(x - 1))#
#=>(2xcancel((x- 1)))/(cancel((x +3))(x - 3)) xx (cancel((x + 3))(x - 1))/((x + 2)cancel((x - 1))#
#=>((2x)(x - 1))/((x - 3)(x + 2))#
Hopefully this helps!
