How do you divide #\frac { 3+ \frac { 30} { p } } { 1- \frac { 100} { p ^ { 2} } }#?

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Answer 1 · 2017-03-04T03:31:27

#(3+30/p)/(1-100/p^2)=(3p)/(p-10)#

#(3+30/p)/(1-100/p^2)#

= #(3(1+10/p))/(1^2-(10/p)^2)#

= #(3(1+10/p))/((1+10/p)(1-10/p))#

= #(3(cancel(1+10/p)))/((cancel(1+10/p))(1-10/p))#

= #3/(1-10/p)#

= #3/((p-10)/p)#

= #3xxp/(p-10)#

= #(3p)/(p-10)#