How do you divide #\frac { 5n ^ { 4} + 40n ^ { 3} } { n ^ { 2} - 19n + 48} \div \frac { 3n ^ { 2} + 15n - 72} { n ^ { 2} - 16n }#?
1 Answer
Dec 21, 2016
Convert to a multiplication.
#=(5n^4 + 40n^3)/(n^2 - 19n + 48) * (n^2 - 16n)/(3n^2 + 15n - 72)#
Factor everything.
#=(5n^3(n + 8))/((n - 16)(n - 3)) * (n(n - 16))/(3(n^2 + 5n - 24))#
#=(5n^3(n + 8))/((n - 16)(n - 3)) * (n(n - 16))/(3(n + 8)(n - 3))#
After eliminating, we are left with:
#=(5n^4)/(3(n + 3)^2)#
With restrictions of:
Hopefully this helps!