Question

How do you divide `(m^3n^2)/(m^-1n^3)`?

Answer 1

`(m^3n^2)/(m^(-1)n^3) = m^4n^-1`

Explanation:

First, let's use the distributive rule to separate the monomials.

`(m^3n^2)/(m^(-1)n^3) = (m^3/m^-1)(n^2/n^3)`

Now we use the quotient rule: when dividing monomials that have the same base, we subtract the exponents.

So

`(m^3/m^-1)(n^2/n^3) = (m^(3-(-1)))(n^(2-3)) =m^(3+1)n^-1`

`(m^3n^2)/(m^(-1)n^3) = m^4n^-1`