Question

How do you divide `(n^3 + 2n^2 - n - 2)` by `(n^2 - 1)`?

Answer 1

Refer to explanation

Explanation:

We have that

#(n^3 + 2n^2 - n - 2)/(n^2 - 1)=(n^3-n+2(n^2-1))/(n^2-1)= (n(n^2-1)+2(n^2-1))/(n^2-1)=((n^2-1)*(n+2))/(n^2-1)=n+2#