How do you divide #(t^2-16)/(t^2-8t+16)#?
1 Answer
Mar 16, 2018
#(t^2-16)/(t^2-8t+16) = 1+8/(t-4)#
Explanation:
#(t^2-16)/(t^2-8t+16) = (color(red)(cancel(color(black)((t-4))))(t+4))/(color(red)(cancel(color(black)((t-4))))(t-4)) = (t+4)/(t-4) = ((t-4)+8)/(t-4) = 1+8/(t-4)#