# How do you divide (t^2-16)/(t^2-8t+16)?

$\frac{{t}^{2} - 16}{{t}^{2} - 8 t + 16} = 1 + \frac{8}{t - 4}$
$\frac{{t}^{2} - 16}{{t}^{2} - 8 t + 16} = \frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{\left(t - 4\right)}}} \left(t + 4\right)}{\textcolor{red}{\cancel{\textcolor{b l a c k}{\left(t - 4\right)}}} \left(t - 4\right)} = \frac{t + 4}{t - 4} = \frac{\left(t - 4\right) + 8}{t - 4} = 1 + \frac{8}{t - 4}$