Question

How do you divide `(x^2)/(2x + 4)`?

Answer 1

It is `1/2*(x^2/(x+2))= x/2+2/(x+2)-1`

Explanation:

It is

`1/2*[x^2/(x+2)]=1/2*[(x^2+2x-2x)/(x+2)]=1/2*[x-(2x)/(x+2)]= 1/2*[x-2*(x+2-2)/(x+2)]=1/2*[x-2*(1-2/(x+2))]= x/2-1+2/(x+2)`