How do you divide $x^{2} - 4 x - 3$ $x^2-4x-3$ by $x + 5$ $x+5$ ?

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How do you divide $x^{2} - 4 x - 3$ $x^2-4x-3$ by $x + 5$ $x+5$ ?

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Answer 1 · 2016-12-23T22:06:40

$x + 1 + \frac{2}{x + 5}$ $x+1 +2/(x+5)$

Explanation:

Divide $x^{2} - 4 x - 3$ $x^2-4x-3$ by $x + 5$ $x+5$ .

$a a a a a a a a a a^{1} a x + 1 + \frac{2}{x + 5}$ $color(white)(aaaaaaaaaa^1a)x+1 +2/(x+5)$
$a a a a a - - - - - - - - - -$ $color(white)(aaaaa)----------$
$x - 5 ∣ a x^{2} - 4 x - 3$ $x-5 | color(white)ax^2-4x-3$
$a a^{2} a - (x^{2} - 5 x) a ⏐ ⏐ ↓$ $color(white)(aa^2a)-(x^2-5x)color(white)(a)darr$
$a a a a a a - - - -$ $color(white)(aaaaaa)----$
$a a a a a a a a a a a a x - 3$ $color(white)(aaaaaaaaaaaa)x-3$
$a a a a a a a a a - (x - 5)$ $color(white)(aaaaaaaaa)-(x-5)$
$a a a a a a a a a - - - -$ $color(white)(aaaaaaaaa)----$
$a a a a a a a a^{2} a a a a a a a 2$ $color(white)(aaaaaaaa^2aaaaaaa)2$

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How do you divide $x^{2} - 4 x - 3$ $x^2-4x-3$ by $x + 5$ $x+5$ ?

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How do you divide x2−4x−3x^2-4x-3 by x+5x+5?

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How do you divide $x^{2} - 4 x - 3$ $x^2-4x-3$ by $x + 5$ $x+5$ ?