# How do you divide  (x^2-5x-14)/(x-7)div(x+2)/(x^2-9)?

$\left({x}^{2} - 5 x - 14\right) = \left(x + 2\right) \left(x - 7\right)$
$f \left(x\right) = \frac{\left(x + 2\right) \left(x - 7\right)}{x - 7} . \frac{{x}^{2} - 9}{x + 2} = \left(x - 3\right) \left(x + 3\right)$