Question

How do you divide `(x^3-1)/(x^2+1) div (9x^2+9x+9)/(x^2-x)`?

Answer 1

`x(x-1)/9`

Explanation:

Note that

`x^3-1=(x-1)(x^2+x+1)`

we get

`(x^3-1)/(x-1)*(x(x-1))/(9(x^2+x+1))`=

`((x-1)(x^2+x+1)*x*(x-1))/(9(x^2+x+1)(x-1))=(x(x-1))/9`