How do you divide #(x^3+9x+8)/(x-7)#?

1 Answer
Jul 22, 2017

There are two ways to handle these; long division and synthetic division, but they will both yield you the same answer.

Explanation:

I sorry that I cannot display it, but I will tell you how to do the problem.

In the dividend, make sure to add a #0x^2# because if you do not this, it can result in a wrong answer.

#(x^3+0x^2+9x+8)/(x-7)#

I recommend the synthetic division in this case because the divisor is a monomial.

I am so sorry that I cannot display the work, but the way to do it is to use the constants in front of every term and adding them to the product of the result before that.

So you end up with:

#x^2+7x+58+(414)/(x-7)#

Again, I sincerely apologize that I cannot display the work.