Question

How do you divide `((x^4y^-2)/(x^-3y^5))^-1`?

Answer 1

`(y/x)^7`

Explanation:

Step 1: Move the power outside the brackets into it:
`((x^4y^-2)/(x^-3y^5))^-1=(x^-3y^5)/(x^4y^-2)`

Step 2: Move the denominator terms into the numerator:
`(x^-3y^5)/(x^4y^-2)=(x^-3y^5)(x^-4y^2)`

Step 3: Combine similar terms:
`(x^-3y^5)(x^-4y^2)=x^-7y^7=(y/x)^7`