# How do you draw the graph of y=2-sinx for 0<=x<2pi?

If we look at $\textcolor{b l u e}{y = 2 - \sin x}$ in relation to $\textcolor{b l u e}{y = \sin x}$, we can see that, if we reflect $\textcolor{b l u e}{y = \sin x}$ in the x axis, we get $\textcolor{b l u e}{y = - \sin x}$. If we then translate this 2 units in the positive y direction we get $\textcolor{b l u e}{y = 2 - \sin x}$ .