# How do you draw the graph of y=-tanx for 0<=x<2pi?

Jul 16, 2018

See the required graph, in-between $x = 0 \mathmr{and} x = 2 \pi$.

#### Explanation:

For x in $\left(0 , 2 \pi\right)$, y= 0, at $x = 0 , \pi , 2 \pi$
,
There are two asymptotes $x = \frac{\pi}{2} \mathmr{and} x = \left(\frac{3}{2}\right) \pi$, within the

interval.

The graph is not on uniform scale, for better visual effect.

graph{ (y+tan x)(x+0y)(x-2pi+0y) = 0[-0.1 6.3 -16 16]}