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# How do you draw the Lewis structure for the hypobromite ion, BrO^-?

Given that $\text{Br}$ has $7$ valence electrons and ${\text{O}}^{-}$ has $7$ valence electrons (i.e. including the $-$ charge), we have $14$ valence electrons to distribute.
$: \ddot{\text{Br"-ddot"O}} {:}^{\left(-\right)}$
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