How do you evaluate $- 0.86 - {(- 0.01 - - 0.81)}^{2}$ $-0.86- ( - 0.01- - 0.81) ^ { 2}$ ?

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Answer 1 · 2017-09-14T21:42:46

$- 0.5504$ $-0.5504$

$- 0.86 {(- 0.01 + 0.81)}^{2}$ $-0.86(-0.01+0.81)^2$

$- 0.86 {(0.80)}^{2}$ $-0.86(0.80)^2$

$- 0.86 (0.64)$ $-0.86(0.64)$

$- 0.5504$ $-0.5504$

How do you evaluate -0.86- ( - 0.01- - 0.81) ^ { 2}−0.86−(−0.01−−0.81)2-0.86- ( - 0.01- - 0.81) ^ { 2}?