How do you evaluate #162div(6(7-4))#?

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Answer 1 · 2017-08-30T12:54:08

#9#

There is only one term, but #3# different operations happening.

Start with the subtraction in the innermost bracket

#=162 div (6(color(red)(7-4)))#

#=162 div (6(color(red)(3)))#

Now multiply to remove the brackets altogether

#=162 div 18#

#=9#