How do you evaluate #16t - 20t = 12#?

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Answer 1 · 2018-03-19T08:14:20

#t=-3#

#16t-20t=12#

Combine like-terms.

#-4t=12#

Divide by #-4#.

#t=12/-4#

#=-3#

Answer 2 · 2018-03-19T08:19:07

#t=-3#

#"simplify left side of equation"#

#rArr-4t=12#

#"divide both sides by "-4#

#(cancel(-4) t)/cancel(-4)=12/(-4)#

#rArrt=-3#