How do you evaluate #2[3(7-5) + 4(8+2)]#?

Question

2066 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-04T06:55:08

Using PEMDAS

#2[3(7 - 5) + 4(8 + 2)]#

P - parentheses which are the brackets.

E - exponents

M - multiplication

D - division

A - addition

S - multiplication

We start with the parentheses..

#2[3(2) + 4(10)]#

#=2[6 + 40]#

#=2[46]#

#=92#

Answer 2 · 2018-03-04T07:08:25

#92#

Start with the inner brackets and simplify each to a single answer.

#2[3(color(blue)(7-5))" "+" "4(color(red)(8+2))]#

#=2[3(color(blue)(2))" "+" "4(color(red)(10))]" "larr# multiply to remove the brackets

#=2[color(blue)(6)" "+" "color(red)(40)]" "larr# simplify inside the square brackets

#=2[color(purple)(46)]" "larr# multiply to remove the square brackets

#=92#

It may seem that the usual order of operations is not being followed here because we do:

However, all of these are just to get rid of the brackets.
There is only only term but we work from the inner brackets, outwards.