# How do you evaluate (-27/8)^(4/3)?

${\left(- \frac{27}{8}\right)}^{\frac{4}{3}}$
$= {\left({\left(- \frac{27}{8}\right)}^{\frac{1}{3}}\right)}^{4}$
$= {\left(\frac{\sqrt[3]{- 27}}{\sqrt[3]{8}}\right)}^{4}$
$= {\left(- \frac{3}{2}\right)}^{4}$
$= \frac{81}{16}$