# How do you evaluate #(2x-3)(3x+2)#?

##### 2 Answers

Sep 22, 2017

#### Explanation:

You just have to expand it.

And that's the answer!

Sep 22, 2017

#### Explanation:

#"each term in the second bracket is multiplied by each"#

#"term in the first bracket"#

#(color(red)(2x-3))(3x+2)#

#=color(red)(2x)(3x+2)color(red)(-3)(3x+2)#

#=(color(red)(2x)xx3x)+(color(red)(2x)xx2)+(color(red)(-3)xx3x)+(color(red)(-3)xx2)#

#=6x^2+4x-9x-6#

#=6x^2-5x-6#