How do you evaluate #3 * (-2) +6 -(-2) - 5#?

3 Answers

Answer:

#-3#

Explanation:

#3(-2)+6-(-2)-5=?#

PEMDAS

#-6+6-(-2)-5#

#-6+6+(2)-5#

combine

#2-5#

#2+ (-5)#

so, the answer is:
#-3#

Apr 30, 2018

Answer:

#-##3#

Explanation:

Use your order of operations.

#3##xx#(#-##2#)#+##6##-#(#-##2#)#-##5#

The parentheses here are only making it obvious that the numbers are negative, so let's get rid of them.

#3##xx##-##2##+##6##-##-##2##-##5#

Next up on the order of operations is exponents, but we don't have any, so we move to multiplication.

#3##xx##-##2#

#3##xx##-##2# is #-#(#3##xx##2#), which is #-##6#

#-##6##+##6##-##-##2##-##5#

Since there is no more multiplication and no division is present, we move on to addition and subtraction. It's pretty easy from here.

#-##6##+##6##=##0#

Next we've got a double negative. Whenever we subtract a negative number, we add instead.

#0##+##2##-##5#

#2##-##5#

#-##3#

Well, that wasn't too hard, was it?

Apr 30, 2018

Answer:

#-3#

Explanation:

Count the number of terms first.
Simplify each term separately.

#color(red)(3xx(-2))" "color(blue)(+6)" "color(green)(-(-2))" "color(purple)(-5)" "larr# there are #4# terms

#=color(red)(-6)" "color(blue)(+6)" "color(green)(+2)" "color(purple)(-5)#

#=" " 0" "+" "2" "-5" "larr (-6+6=0)#

#=-3#