How do you evaluate #[(30 + 6) − 32] ÷ 9 * 2#?

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Answer 1 · 2015-12-22T15:22:45

Question not definitively clear as to intention.
I got #2/9 .color(white)(..)# Have a look at the method. Particularly at the end.

Given: #[(30+6)-32] -: 9 xx 2#

Note that formatting star gives you #*#
Formatting a full stop gives you #.#

So the original question ends with 9 times 2 and not 9 point 2

There are two interpretations as to what the question proposer was after.

Intention 1: #[(30+6)-32] -: (9 xx 2)#

Intention 2: #((30+6)-32)/(9) xx 2#

#color(blue)("Assumption: Intention 1 is the case.")#

Write as

#(30+6-32)/(9xx2) = (6-2)/(9xx2) = 4/18#

#color(brown)("Divide top and bottom by 2 giving")#

#(4-:2)/(18-:2) =2/9#