Question

How do you evaluate `4tan((-3pi)/4)+sin(-pi/4)`?

Answer 1

`(4 - sqrt2/2)`

Explanation:

Trig unit circle and trig table -->
`tan ((-3pi)/4) = tan (pi/4) = 1`
`4tan ((-3pi)/4) = 4`
`sin (-pi/4) = - sin (pi/4) = - sqrt2/2`

The sum is equal to: `4 - sqrt2/2`