How do you evaluate #5^2*(-3)-4*6+7#?

2 Answers
Sep 16, 2016

Answer:

#- 92#

Explanation:

We have: #5^(2) cdot (- 3) - 4 cdot 6 + 7#

Let's use the rules of operator precedence, "PEMDAS":

#= 25 cdot (- 3) - 4 cdot 6 + 7#

#= - 75 - 4 cdot 6 + 7#

#= - 75 - 24 + 7#

#= - 99 + 7#

#= - 92#

Sep 16, 2016

Answer:

#-92#

Explanation:

In any expression with different operations, it is important to COUNT terms first. Each term will simplify to a single answer.

Within each term the order of operations is applied:
Brackets
Powers and roots
multiply and divide

You can work in different terms in the same line.

Once there is a single answer to each term, these are added or subtracted in the last step, working from left to right.

#color(red)(5^2)xx(-3) color(blue)(-4xx6)color(lime)(+7)" "larr# there are 3 terms

=#color(red)(25xx(-3) color(blue)(-24)color(lime)(+7)#

=#color(red)(-75) color(blue)(-24)color(lime)(+7)#

It is often easier to re-arrange the terms with the plus terms at the beginning and the minus terms at the end.

=#color(lime)(+7)color(red)(-75) color(blue)(-24)#

=#-92#