How do you evaluate #5(3+12) + 42(23-4) #?

2 Answers
Jul 7, 2015

Answer:

Distribute the #5# and the #42#. Add and subtract from left to right.

Explanation:

Distribute the #5# and the #42#.

Multiply #5# times the terms in the first set of parentheses, and multiply #42# times the terms in the second set of parentheses.

#5*3+5*12+42*23-42*4# =

#15+60+966-168# =

Add and subtract from left to right.

#1041-168=873#

Jul 7, 2015

Answer:

Rather than distributing to remove the parentheses, you could do the parentheses first, then multiply, then add.

Explanation:

#5(3+12) + 42(23-4)#

# = 5(15)+42(19)#

# = 75 + 798#

# = 873#