How do you evaluate #(5/9 - 3)/(5/6) -:3/2 -: 3/4#?

1 Answer
Feb 27, 2017

#(5/9-3)/(5/6)-:3/2-:3/4=-352/135#

Explanation:

Dividing a fraction by a fraction, whether as in #(a/b)/(c/d)# or #a/b-:c/d#, is equivalent to multiplying by the reciprocal or multiplicative inverse of denominator (or the fraction written after sign ''#-:# and hence

#(a/b)/color(red)(c/d)=a/bcolor(red)(-:c/d)=a/bcolor(red)(xx(d/c))#

Now #5/9-3=5/9-(3xx9)/(1xx9)=5/9-27/9=(5-27)/9=-22/9#

Hence #(5/9-3)/(5/6)-:3/2-:3/4#

= #(-22/9)/(5/6)-:3/2-:3/4#

= #-22/9xx6/5xx2/3xx4/3#

= #-22/9xx(2cancel6)/5xx2/(1cancel3)xx4/3#

= #-(22xx2xx2xx4)/(9xx5xx3)#

= #-352/135#