How do you evaluate 5 radical 16/3 - radical 9/2?

1 Answer
Nov 9, 2015

Answer:

#20/sqrt(3)-3/sqrt(2)#

Explanation:

You have that #sqrt(a/b)=sqrt(a)/sqrt(b)#. So,

#sqrt(16/3) = sqrt(16)/sqrt(3) = 4/sqrt(3)#.

Also,

#sqrt(9/2)=sqrt(9)/sqrt(2) = 3/sqrt(2)#

Now that we have simplified the radicals, we can write the whole expression:

#5*4/sqrt(3) - 3/sqrt(2) = 20/sqrt(3)-3/sqrt(2)#