How do you evaluate #(5z)^ -x# for z=-3 and x=2?

1 Answer
Jan 6, 2017

Answer:

#1/225#

Explanation:

Using the #color(blue)"law of exponents"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(a^-mhArr1/a^m)color(white)(2/2)|)))#

substituting the given values for x and z into the expression.

#rArr(5z)^-x=(5xx-3)^-2=(-15)^-2#

#=1/(-15)^2=1/225#