Question

How do you evaluate `(6.23 x\times 10^6 kL)+ (5.34 \times 10^5 kL)`?

Answer 1

Please see below.

Explanation:

One thing to ask is that how `x` has appeaared in first term. If it is there as desired, we proceed as under.

Here numbers are mentioned in scientific notation. Hence to add them we first convert them to same power of `10`, so that we can use distributive property to add them. This is done as follows:

`(6.23x xx10^6 kL)+(5.34xx10^5kL)`

= `(6.23x xx10xx10^5 kL)+(5.34xx10^5kL)`

= `62.3x xx10^5kL+5.34xx10^5kL`

= `(62.3x+5.34)xx10^5kL`

Here, if we put any value of `x`, we can modify it to pure scientific notation. (see below how to do it)

In case `x` is inadvertant, we can get the result in pure scientific notation as follows:

`62.3xx10^5kL+5.34xx10^5kL`

= `(62.3+5.34)xx10^5kL`

= `67.64xx10^5kL`

= `6.764xx10xx10^5kL`

= `6.764xx10^6kL`