# How do you evaluate #6(abs(x+y))# when x=1, y=1?

##### 1 Answer

Dec 6, 2016

#### Explanation:

To evaluate the expression, substitute x = 1 and y = 1 in for x and y in the expression.

#rArr6(|x+y|)=6(|1+1|)=6(|2|)# The

#color(blue)"absolute value"# is always positive. The reason being that it gives a measure of how far a number is from zero, irrespective of it's sign.That is

#|-4|=|4|=4# as both 4 and - 4 are 4 units from zero.

#rArr6(|2|)=6xx2=12#