Question

How do you evaluate `6(abs(x+y))` when x=1, y=1?

Answer 1

`12`

Explanation:

To evaluate the expression, substitute x = 1 and y = 1 in for x and y in the expression.

`rArr6(|x+y|)=6(|1+1|)=6(|2|)`

The `color(blue)"absolute value"` is always positive. The reason being that it gives a measure of how far a number is from zero, irrespective of it's sign.

That is `|-4|=|4|=4` as both 4 and - 4 are 4 units from zero.

`rArr6(|2|)=6xx2=12`